There are two containers of chlorine solutions, the first container contains a mixture of...
Qualcomm technical mcq question, verified with a worked answer. Free to practise - no sign-up.
There are two containers of chlorine solutions, the first container contains a mixture of 70% chlorine and 30% water while the second container contains a mixture of 40% chlorine and 60% water. If 30 liters of the first solution is mixed with 20 liters of the second solution, what is the percentage of chlorine in the resulting mixture?
Show answer & explanation
Calculate the amount of chlorine from each container: first container contributes 30 × 0.70 = 21 liters of chlorine, second container contributes 20 × 0.40 = 8 liters of chlorine. Total chlorine = 21 + 8 = 29 liters in a total mixture of 30 + 20 = 50 liters. Percentage = (29/50) × 100 = 58%.
Step-by-step Derivation:
Step 1: Calculate chlorine from container 1
Volume = 30 liters
Chlorine concentration = 70%
Chlorine amount = 30 × 0.70 = 21 liters
Step 2: Calculate chlorine from container 2
Volume = 20 liters
Chlorine concentration = 40%
Chlorine amount = 20 × 0.40 = 8 liters
Step 3: Calculate total chlorine and total volume
Total chlorine = 21 + 8 = 29 liters
Total volume = 30 + 20 = 50 liters
Step 4: Calculate percentage of chlorine in mixture
Percentage = (Total chlorine / Total volume) × 100
Percentage = (29 / 50) × 100 = 0.58 × 100 = 58%