The ages of Mohit and Amit differ by 30 years.
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The ages of Mohit and Amit differ by 30 years. 5 years later, Mohit is 6 times as old as Amit.
**MCQ
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Setting up equations: Let Amit's current age be x and Mohit's be x+30 (since they differ by 30). In 5 years, Amit will be x+5 and Mohit will be x+35. Given that Mohit is then 6 times Amit's age: x+35 = 6(x+5), which simplifies to x+35 = 6x+30, giving x = 1... Wait, let me recalculate. Actually x+35 = 6(x+5) → x+35 = 6x+30 → 5 = 5x → x = 1. But this doesn't match option B. Let me verify: if Amit is currently 1, Mohit is 31. In 5 years, Amit is 6 and Mohit is 36. Is 36 = 6×6? Yes. So the answer should be D) 1 year. However, given the options provided and standard problem formulation, if we assume Amit is currently 7: Mohit is 37. In 5 years: Amit is 12, Mohit is 42. Is 42 = 6×12? No. There appears to be an inconsistency in the problem or options provided. The mathematically correct answer is 1 year (Option D), but Option B is listed as the provided correct answer.
Step-by-step Derivation:
Let Amit's current age = x years, Mohit's current age = x + 30 years. After 5 years: Amit's age = x + 5, Mohit's age = x + 35. Given: Mohit's age after 5 years = 6 × Amit's age after 5 years. Therefore: x + 35 = 6(x + 5) → x + 35 = 6x + 30 → 35 - 30 = 6x - x → 5 = 5x → x = 1. Verification: Current ages are Amit = 1, Mohit = 31. After 5 years: Amit = 6, Mohit = 36. Check: 36 = 6 × 6 ✓. Amit's current age is 1 year (Option D).