It is given that a dog barks once every two minutes and a cat meows on average once every...
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It is given that a dog barks once every two minutes and a cat meows on average once every five minutes.
The number of times a dog would bark in 24 hours is approximately equal to what percent greater than the number of times a cat would meow in that same period?
Show answer & explanation
In 24 hours (1440 mins), dog barks 720 times and cat meows 288 times. Percentage greater is (720 - 288) / 288 * 100% = 432 / 288 * 100% = 150%.
Step-by-step Derivation:
Step 1: Total minutes in 24 hours = 24 * 60 = 1440 minutes.
Step 2: Dog barks = 1440 / 2 = 720 times.
Step 3: Cat meows = 1440 / 5 = 288 times.
Step 4: Percentage greater = ((720 - 288) / 288) * 100% = (432 / 288) * 100% = 150%.