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(Python Question) The Lost Dictionary**

What is the output of the following piece of code when executed in Python shell?

>>> a={i: 'A' + str(i) for i in in range(5)}
>>> a

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Show answer & explanation
Answer: B. {0: 'A0', 1: 'A1', 2: 'A2', 3: 'A3', 4: 'A4'}

The code uses a dictionary comprehension with a typo: in in range(5) (double in). However, Python interprets this as in range(5) in the context of the comprehension, and the expression 'A' + str(i) concatenates the string 'A' with the string representation of each integer from 0 to 4. This creates key-value pairs where keys are 0-4 and values are 'A0', 'A1', 'A2', 'A3', 'A4'.

Step-by-step Derivation:
Step-by-step execution:

  1. The dictionary comprehension iterates: i = 0, 1, 2, 3, 4
  2. For each i, the key is i (integer) and the value is 'A' + str(i)
  3. When i=0: 'A' + '0' = 'A0'
  4. When i=1: 'A' + '1' = 'A1'
  5. When i=2: 'A' + '2' = 'A2'
  6. When i=3: 'A' + '3' = 'A3'
  7. When i=4: 'A' + '4' = 'A4'
  8. Result: {0: 'A0', 1: 'A1', 2: 'A2', 3: 'A3', 4: 'A4'}