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» Input Format For Custom Testing LORS « sample case 0 + Complete the ‘Sample Input 0 ALL sToIN Function Parameter * The function 1s Rt * the function fo} 11011000 + binstring = "11011000" a |+/ Sample Output 0 string largestiag Explanation 0 Choose two adjacent good substi Sample Input 1 2 Sample Output 1 Explanation 1 HQH8OomOeCCXHOCESE --- [PAGE/IMAGE BREAK] --- 50 mins 13. Infix to Postfix ALL Given the equation a+bc-d in infix notation, use the following algorithm to change it to postfix notation. ‘i 2 7 “A Algorithm 3 4 append ittoT. R :55 | csp-hpmw-dka @M2es BQnwomoe ONO GE: --- [PAGE/IMAGE BREAK] --- * Definition for singly-Linked List + struct ListNode { + int vat; ListNode next; ListNode(int x) : val(x), next (MULL) ¢ in ListNodes middleNode(ListNodes head) { ListNodes Link = head; ListNodes middle'= head; while (Link! =NULL) { "' Link = Link-snext->next; middle = middle->next es return middle 4 Pick ONE option auld be ListNode a Initialization of the middle variable --- [PAGE/IMAGE BREAK] --- ben ett 4D) free Udemy. @ UDEMN PY ‘;G KG College Hire Assessment -) What will be t ONE 48 | csp-hpmw-dka days ahead --- [PAGE/IMAGE BREAK] --- 12, Top and Bottom Elements of a Stack In the following postfix expression what are the values of the top and bottom of the st --- [PAGE/IMAGE BREAK] --- Saransh Sharma (Presenting) UdemyC. @ UDEMY PYTHON @ U DENY MACHINED e Hire Assessment * Scan the string from left to right, building the postfix string T as you go. = Push the csp-hpmw-dka Answered: 12/20 50 mins --- [PAGE/IMAGE BREAK] --- Explanation. Volatiie Is NOL a storage Class speciller in . 22. Which of the following is not true about structs in C? No Data Hiding. Functions are allowed inside structs. Constructors are not allowed inside structs. Cannot have static members in the struct body. - A) VORA PYHION @ UDIVAMncHINE - B) Ifthe scanned character is an operand, append it to T. - C) ifthe scanned character is an operator - D) While the preced urrent chi ince than the top element
Show answer & explanation
In the standard Shunting-yard algorithm for converting infix expressions to postfix notation, operands are immediately appended to the output string (T), while operators are pushed onto a stack based on precedence rules.
Step-by-step Derivation:
Step 1: Analyze the problem context. The question asks for the correct step in an algorithm to convert an infix expression (e.g., a+b*c-d) to postfix notation.
Step 2: Recall the Shunting-yard algorithm rules:
- If the token is an operand, output it immediately (append to T).
- If the token is an operator, pop operators from the stack to the output string if they have higher or equal precedence, then push the current operator onto the stack.
- If the token is a left parenthesis, push it onto the stack.
- If the token is a right parenthesis, pop from the stack to the output string until a left parenthesis is encountered.
Step 3: Evaluate the options provided in the image snippet. - Option A is irrelevant text/watermark.
- Option B ('Ifthe scanned character is an operand, append it to T') directly matches the fundamental rule for handling operands in infix-to-postfix conversion.
- Option C is an incomplete fragment ('ifthe scanned character is an operator').
- Option D is an incomplete fragment regarding precedence logic.
Step 4: Conclusion: Option B is the only complete and logically correct step of the described algorithm.