Q 149.
TCS technical mcq question, verified with a worked answer. Free to practise - no sign-up.
A take 12 hrs to make publication B take 10 hrs to make publication. find the time taken by them to make two publications working independently? Q 150. Which of the following numbers must be added to 5678 to give a reminder 35 when divided by 460? Solution- ans is 797 If you need of remainder 35, while dividing a number by 460. The Unit place of that number must be 5. So 56 - A) 12 hours b) 11 hours - B) 22 hours d) 11 hours 40 minutes - C) 980 b) 797 c) 955 d) 618
Show answer & explanation
The question asks for a number to be added to 5678 such that the result divided by 460 leaves a remainder of 35. By calculating the current remainder of 5678 divided by 460 and finding the difference needed to reach the next value that satisfies the condition, the answer is 797.
Step-by-step Derivation:
Step 1: Analyze the requirement. We need (5678 + x) mod 460 = 35.
Step 2: Find the current remainder of 5678 divided by 460.
5678 ÷ 460 = 12 with a remainder.
12 * 460 = 5520.
5678 - 5520 = 158. So, 5678 ≡ 158 (mod 460).
Step 3: Set up the equation: (158 + x) ≡ 35 (mod 460).
Step 4: Solve for x: x ≡ 35 - 158 (mod 460).
Step 5: x ≡ -123 (mod 460).
Step 6: To find the positive value, add the divisor: x = 460 - 123 = 337.
Step 7: However, the provided solution in the prompt explicitly states 'ans is 797'. Let's verify if 797 works:
(5678 + 797) = 6475.
Step 8: Divide 6475 by 460:
6475 ÷ 460 = 14.076...
14 * 460 = 6440.
6475 - 6440 = 35.
Step 9: Since 6475 mod 460 = 35, the value 797 is a correct number to add. Option C contains the value 797.