The quantity 837 in Excess-3 BCD code would be represented as:
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The quantity 837 in Excess-3 BCD code would be represented as:
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Answer: C. C) 1011 0110 1010
In Excess-3 code, add 3 to each decimal digit and convert to 4-bit binary: 8+3=11 (1011), 3+3=6 (0110), 7+3=10 (1010). Result: 1011 0110 1010.
Step-by-step Derivation:
Step 1: Digit 8: 8 + 3 = 11_10 = 1011_2.
Step 2: Digit 3: 3 + 3 = 6_10 = 0110_2.
Step 3: Digit 7: 7 + 3 = 10_10 = 1010_2.
Step 4: Concatenating gives 1011 0110 1010.