QUESTION 15 --- The present age of a father is four times that of his son.
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The present age of a father is four times that of his son. In 10 years, the father's age will be 20 years more than twice the son's age. What is the son's current age?
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Answer: C. C) 15 years
F = 4S. In 10 years: 4S + 10 = 2(S + 10) + 20 => 4S + 10 = 2S + 40 => 2S = 30 => S = 15 years.
Step-by-step Derivation:
Step 1: F = 4S.
Step 2: F + 10 = 2(S + 10) + 20.
Step 3: 4S + 10 = 2S + 40 => 2S = 30 => S = 15 years.