Instructions: Given signs signify something and on that basis, assume the given statements...
Cognizant technical mcq question, verified with a worked answer. Free to practise - no sign-up.
Instructions:**
Given signs signify something and on that basis, assume the given statements to be true and find which of the two conclusions I and II is/are definitely true.
- "#" denotes "greater than"
- "/" denotes "equal to"
- "&" denotes "not equal to"
- "+" denotes "lesser than"
- "%" denotes "a little more than"
- "'" denotes "a little less than"
If A#B and B%C, then
Show answer & explanation
Answer: B. C+A (C is lesser than A)
From A#B, we have A > B. From B%C, we have B is slightly greater than C (B ≈ C, but B > C). By transitivity: A > B and B > C implies A > C. Therefore, C < A, which is written as C+A in the given notation.
Step-by-step Derivation:
Step 1: Decode the given statements.
- A#B means A > B
- B%C means B is a little more than C, i.e., B > C (with B ≈ C)
Step 2: Apply transitivity of inequality.
- A > B and B > C
- Therefore, A > C
Step 3: Express in the given notation.
- A > C is equivalent to C < A
- C < A is written as C+A (using '+' for 'less than')
Step 4: Verify other options.
- Option A (A+C): This means A < C, which contradicts A > C. FALSE.
- Option C (C%A): This means C is a little more than A, which contradicts A > C. FALSE.